@Popi said:
Thanks for that, i’m kinda new to linux and was hoping to find just that.
1 more question though: why the “s” in “sed s/,$//” ?
Because you are using the search and replace functionality.
You can find out more about sed with examples here: https://linuxconfig.org/learning-linux-commands-sed
i know the comma and the slash are escaped with the “/”, $ is end of line,
Well, not really here. An escape in bash is normally \.
Doing a replace with sed is basically the format:
sed 's/search/replace/g'
So they aren’t escapes in this context. It is search for , at the end of a line and replace with /.
but still can’t figure out what the “s” is for. is it just to prevent it from reading the first “/” as an argument? like it could in fact be any letter?
No.